A quadratic equation can have no real solution
a\(a x^{2} +bx+c=0\)
If \(b^{2} -4ac\ \textless \ 0\) then the equation has no real solutions
Even simultaneous equations can have no solutions
\(ax+by=c------1\)
\(ax+by=d------2\)
I these two equations the two expressions equal different things, so the equation has no solutions