solve algebraically for all values of x
1) cross multiply both sides. 3x^2-24= 2x^2+10x^2-10x-24=0x^2-12x+2x-24=0x(x-12)+2(x-12)=0(x-12) (x+2)=0 Bring -12 and 2 to the other side. Therefore the value of x are 12 and -2.
