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Evaluate cube root of 7 multiplied by the square root of 7 over sixth root of 7 to the power of 5.

A7 to the −1st power
B1
C7
D7 to the power of 5 over 3

Verified Answer :

TheBlueLight

I hope u can understanx this. Write it all as exponential and than use the theorems to evaluate, the answer is 1

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calculista

Answer:

The answer is the option b

\(1\)

Step-by-step explanation:

we have

\((\sqrt[3]{7} *\sqrt{7})/\sqrt[6]{7^{5}}\)

we know that

\((\sqrt[3]{7} *\sqrt{7})/\sqrt[6]{7^{5}}=(7^{\frac{1}{3}} *7^{\frac{1}{2}})/7^{\frac{5}{6}}\\ =7^{\frac{5}{6}}/7^{\frac{5}{6}}\\=1\)

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