Explanation:
It is given that,
Input force, \(F_i=2\ N\)
Output force, \(F_o=5\ N\)
Input distance, \(d_i=10\ N\)
Output distance, \(d_o=2\ N\)
1. IMA of a machine is the ratio of input distance to the output distance. It is given by :
\(IMA=\dfrac{d_i}{d_o}=\dfrac{10}{2}=5\)
2. AMA is the actual mechanical advantage of the machine. It is the ratio of output force to the input force. It is given by :
\(AMA=\dfrac{F_o}{F_i}=\dfrac{5}{2}\)
3. The efficiency of the machine is the percentage of output work to the input work.
\(\eta=\dfrac{W_o}{W_i}\times 100\)
\(\eta=\dfrac{F_o\times d_o}{F_i\times d_i}\times 100\)
\(\eta=\dfrac{5\times 2}{2\times 10}\times 100\)
\(\eta=50\%\)
Hence, this is the required solution.
