The specification for a length x is 43.6 cm with a tolerance of 0.1 cm. Write the specification as an absolute value inequality.
My answer to the problem is as follows:
Expressed as an absolute value.
The difference between the actual length, x, and the specification, 43.6, can be no more than 0.1
|x - 43.6| ≤ 0.1 <–––––
The 43.6 is the target length, and the tolerance of 0.1 is how far off from the target is acceptable.
Answer:
\(43.5\leq x\leq 43.7\)
Step-by-step explanation:
We have been given that the specification for a length x is 43.6 cm with a tolerance of 0.1 cm. We are asked to write given specification as an absolute value.
\(|\text{Actual-Ideal}|\leq \text{Tolerence}\)
Upon substituting our given values, we will get:
\(|x-43.6|\leq 0.1\)
Using absolute value definition \(|x|\leq a=-a\leq x\leq a\), we will get:
\(-0.1\leq x-43.6\leq 0.1\)
\(-0.1+43.6\leq x-43.6+43.6 \leq 0.1+43.6\)
\(43.5\leq x \leq 43.7\)
Therefore, our required inequality would be \(43.5\leq x \leq 43.7\).