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A quadratic function has a line of symmetry at x = –3 and a zero at 4.


Q1: What is the distance from the given zero to the line of symmetry?


Q2: What is the other zero of the quadratic function?

Verified Answer :

I have my hints here on how to solve the questions one and two:

Q1: Just find the distance from -3 to 4. That's 7.


Q2: It is 7 units to the left of -3. Subtract 7 from -3. That's -10

I hope my answer has come to your help. God bless and have a nice day ahead!

calculista

Answer:

Part 1) \(7\ units\)

Part 2) The other zero is \(-10\)

Step-by-step explanation:

we know that

If the line of symmetry is equal to \(x=-3\)

then

the quadratic function is a vertical parabola and the x-coordinate of the vertex is \(-3\)

Part 1) What is the distance from the given zero to the line of symmetry?

The distance is equal to the absolute value of the difference of \(-3\) from \(4\)

\(d=\left|4-\left(-3\right)\right|=7\ units\)  

Part 2) What is the other zero of the quadratic function?

we know that

In a quadratic function the distance from the zero's to the line of symmetry is equal

so

Subtract \(7\) from \(-3\)

\(-3-7=-10\)

The other zero is \(-10\)




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