Answer : The correct option is, (C) 0.50 liters
Solution :
According to the neutralization law,
\(M_1V_1=M_2V_2\)
where,
\(M_1\) = molarity of concentrated HCl solution = 12.0 M
\(V_1\) = volume of concentrated HCl solution = ?
\(M_2\) = molarity of HCl solution = 3.0 M
\(V_2\) = volume of HCl solution = 2.0 L
Now put all the given values in the above law, we get the volume of concentrated HCl solution.
\((12.0M)\times V_1=(3.0M)\times (2.0L)\)
\(V_1=0.50L\)
Therefore, the volume of 12.0 M concentrated HCl required will be, 0.50 liters.
