The point P(3, 4) is on the terminal side of θ. Evaluate tan θ.
The answer to the problem is as follows:
tan θ = ∆y/∆x = (4-0)/(3-0) = 4/3
Therefore, the tan theta evaluated would be 4/3
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Answer:
The value of tan θ is \(\frac{4}{3}\).
Step-by-step explanation:
The point P(3, 4) is on the terminal side of θ.
\(\tan\theta=\frac{perpendicular}{base}\)
From the figure it is noticed that the perpendicular is 4 units and base is 3 units.
\(\tan\theta=\frac{4}{3}\)
Or it can be written as
\(\tan\theta=\frac{y_2-y_1}{x_2-x_1}=\frac{4-0}{3-0}=\frac{4}{3}\)
Therefore the value of tan θ is \(\frac{4}{3}\).