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Verified Answer :

Real numbers can't take the square root of a neg ative number.

Therefore the answers are:

a. (-16)^1/5

c. (-4)^1/3

In the real number set, you can't take an even-indexed root of a negative number.

I hope my answer has come to your help. God bless and have a nice day ahead!

Answer: \((-16)^{\frac{1}{5}}\) And \((-4)^{\frac{1}{3}}\)

Step-by-step explanation:

If there is a negative number inside a square root or if a negative number has power 1/2 then it is called a non real number or complex number.

In expression \((-16)^{\frac{1}{5}}\)  

Negative number is not inside the square root.

⇒ It is a real number.

In expression \((-10)^{\frac{1}{4}}=((-10)^{\frac{1}{2}})^{\frac{1}{2}}\)  

Negative number is inside the square root.

⇒ It is a non real number

In expression \((-4)^{\frac{1}{3}}\)  

Negative number is not inside the square root.

⇒ It is a real number

In expression \(-32^{\frac{1}{3}}=((-32)^{\frac{1}{3}})^{\frac{1}{2}}\)  

Negative number is inside the square root.

⇒ It is a not real number.