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check my work please

a rigid container of O2 has a pressure of 340 kPa at a temperature of 713 k what is the pressure at 273 k? show work

my answer:

[P1 ] [ V1 ] / [ T1 ] = [ P2 ] [ V2 ] / [ T2 ]


[ P2 ] = [ P1 ] [ V1 / V2 ] [ T2 / T1 ]


[ P2 ] = [ 340 ] [ 1.000 ] [ 273.0 / 713.0 ] = 130 kPa.

Verified Answer :

MissPhiladelphia

We can use the ideal gas equation which is expressed as PV = nRT. At a constant volume and number of moles of the gas the ratio of T and P is equal to some constant. At another set of condition, the constant is still the same. Calculations are as follows:

T1/P1 = T2/P2

P2 = T2 x P1 / T1

P2 = 273 x 340 / 713

P2 = 130 kPa

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