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Find the sum of a 10-term geometric sequence when the first term is 3 and the last term is 59,049 and select the correct answer below.


177,147

88,572

88,575

177,144

Verified Answer :

First, we need to solve for the common ratio from
the data given by using the equation.


a(n) = a(1) r^(n-1)

59049 = 3 r^(10-1)

19683 = r^9
r = 3


Then, we can find the sum by the expression:


S(n) = a(1) ( r^n -1) / 1-r

S(10) = 3 (3^10  -1  ) / 3-1
S(10) =88572

zame

Answer:

B) 88572

Step-by-step explanation: