Let the angle between a and b be x then,
x = arccos((a^2 + b^2 - b^2)/2ab = arccos(a/2b)
x = arccos(2/2(3.236)) = arccos(1/3.236) = arccos(0.3090) = 80°
Thus, the angle opposite c = 180 - 80 = 100°
Therefore, c = sqrt(a^2 + b^2 - 2abcos C) = sqrt(2^2 + 3.236^2 - 2(2)(3.236)cos 100) = sqrt(14.471696 + 2.247702) = sqrt(16.719398) = 4.089
c = 4.089
