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A student inscribes a triangle within a semicircle. What is the measure of ∠XYZ?

A90°
B60°
C45°
D120°

A student inscribes a triangle within a semicircle. What is the measure of XYZ? a. 90 b. 60 c. 45 d. 120 class=

Verified Answer :

we know that

The inscribed angle measures half that of the arc that comprises

In this problem

∠XYZ------> is the inscribed angle

∠XYZ=\(\frac{1}{2}[arc\ XZ]\)

\(arc\ XZ=180\°\) ------> because is a diameter of the circle

substitute

∠XYZ=\(\frac{1}{2}[180\°]=90\°\)

therefore

the answer is the option A

\(90\°\)


Answer: a. 90°


Step-by-step explanation:

We know that the in a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.

In the problem∠XYZ is the inscribed angle

∠XYZ=\(\frac{1}{2}\ arc(XZ)\)

⇒ ∠XYZ=\(\frac{1}{2}\angle{XZ}\)

Since XZ is a diameter of the circle which is a line segment, thus ∠XZ=180°

∴ ∠XYZ=\(\frac{1}{2}180^{\circ}=90^{\circ}\)

∴ ∠XYZ=\(90^{\circ}\)

Therefore, a. 90° is the measure of ∠XYZ.