A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total distance and total displacement of the boat?

1) the total distance is the sum of the two distances

60 km + 45 km = 105 km

2) The displacement is the net movement, or the difference between the initial position and the final position

Call x the initial position, then the final position is x + [60km - 45km]

And the displacement is x + (60km - 45km) - x =60km -45 km = 15 km

Answer Link

PiaDeveau PiaDeveau · Answer 2 · 2019-03-10T13:23:14-04:00

Answer:

Total distance = 60 + 45 = 105 km , Total displacement = 60 - 45 = 25 km.

Step-by-step explanation:

Given : A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A.

To find : What are the total distance and total displacement of the boat?

Solution : Let boat's initial point is A.

It moves form A to B = 60 km.

it reverse its direction and move toward A = 45 km at any point .

So, Total Distance = Total path covered by boat.

Total distance = 60 + 45 = 105 km.

Total displacement = initial point - final point.

So, Total displacement = 60 - 45 = 15 km.

Therefore ,Total distance = 60 + 45 = 105 km , Total displacement = 60 - 45 = 15 km.