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Which best describes the end behavior of y=7x^2?


As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) decreases.


As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) decreases.


As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) increases.


As x > 0 increases, f(x) decreases. As x < 0 decreases, f(x) increases.

Verified Answer :

diene

As x > 0 increases, f(x) increases. As x < 0 decreases, f(x) increases. 
because f(x) is a quadratic with lowest point at x=0

Answer:

Option C is correct.

as x > 0 increases, f(x) increases,

as x < 0 decreases, f(x) increase.

Step-by-step explanation:

Given the function: \(y = 7x^2\)

Degree of the polynomial states that the sum of the exponents of each variable in the expression.

The degree of \(7x^2\) is 2 i.e Even

The  leading coefficient of the polynomial \(7x^2\) is, 7 i.e, Positive.

End behavior of the polynomial is the behavior of the graph of  f(x) as x approaches positive infinity or negative infinity.

Also, the degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

Since, the degree of the given function is even and the leading coefficient is positive.

End behavior of the function\(y = 7x^2\) is:

as \(x \rightarrow +\infty\), then  \(f(x) \rightarrow +\infty\)

and

as  \(x \rightarrow -\infty\) , then  \(f(x) \rightarrow +\infty\)

Therefore, as x > 0 increases, f(x) increases.

As x < 0 decreases, f(x) increases.

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