Answer:
\(-5 - (3^2 +2)\) D) −16
\(2^2 - 3 \cdot 6\) C) −14
\(-2 + 4 \cdot 3^2 - 6\) A) 28
\(5 + (4^2 \div 2)(3)\) B) 29
Step-by-step explanation:
Order of operations:
B - Bracket
O - Of
D- Division
M-Multiplication
A-Addition
S-Subtraction
1)\(-5 - (3^2 +2)\)
Solving the expression using rule
\(\Rightarrow -5 - (9+2)\)
\(\Rightarrow -5 - (9+2)\)
\(\Rightarrow-16\)
So, D) −16 is the solution of \(-5 - (3^2 +2)\)
2)\(2^2 - 3 \cdot 6\)
\(\Rightarrow 4 - 18\)
\(\Rightarrow -14\)
So, C) −14 is the solution of \(2^2 - 3 \cdot 6\)
3)\(-2 + 4 \cdot 3^2 - 6\)
\(\Rightarrow - 2 + 4 \cdot 9 - 6\)
\(\Rightarrow - 2 +36 - 6\)
\(\Rightarrow 28\)
So, A) 28 is the solution of \(-2 + 4 \cdot 3^2 - 6\)
4) \(5 + (4^2 \div 2)(3)\)
\(\Rightarrow 5 +(16 \div 2)(3)\)
\(\Rightarrow 5 +(8)(3)\)
\(\Rightarrow 5 +24\)
\(\Rightarrow 29\)
So, B) 29 is the solution of \(5 + (4^2 \div 2)(3)\)
