If the discriminant is zero in a quadratic formula, determine the number of real solutions for that quadratic formula. Please help.
Keywords
discriminant, quadratic equation, real solution
we know that
The formula to calculate the solutions of the quadratic equation of the form \(ax^{2} +bx+c=0\) is equal to
\(x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}\)
where
The discriminant of the quadratic equation is equal to
\(b^{2}-4ac\)
in this problem we have that
\(b^{2}-4ac=0\)
so
substitute in the formula
\(x=\frac{-b(+/-)\sqrt{0}}{2a}\)
\(x=-\frac{b}{2a}\) -------> is one real solution
therefore
The answer is
one real solution
The discriminant gives the type of solutions that will be found for a
quadratic equation.
The number of real solutions for the quadratic formula is one.
Reasons:
If the discriminant in the quadratic formula, y = a·x² + b·x + c, is the value;
\(\mathbf{b^{2}-4\cdot a\cdot c}}\ \ in \ x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}\)
Where;
a, b, and c are real numbers, we have
A zero discriminant gives;
\(x = \dfrac{-b\pm \sqrt{0}}{2\cdot a} = \dfrac{-b\pm0}{2\cdot a} = \dfrac{-b}{2\cdot a}\)
Therefore;
\(x = \dfrac{-b}{2\cdot a}\)
\(\dfrac{-b}{2\cdot a}\) is one real number
Therefore;
The number of real solutions for the quadratic formula is one.
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