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A pyrotechnician plans for two fireworks to explode together at the same height in the air. They travel at speeds shown below. Firework B is launched 0.25 s before Firework A. How many seconds after Firework B launches will both fireworks​ explode?

360 ft/s

280 ft/s

Verified Answer :

The ANWSER is 825 I hope I helped u

fichoh

Representing the scenario using the distance equation, the number of seconds in which explosion would occur is 1.125 seconds.

Recall :

  • Distance = Speed × time
  • Let time = t

Firework A :

  • D(t) = 360t - - - (1)

Firework B:

  • D(t) = 280(0.25) + 280t
  • D(t) = 70 + 280t - - - (2)

Equate (1) and (2) :

360t = 280t + 70

Collect like terms

360t - 280t = 70

80t = 70

t = 70/80

t = 0.875 seconds

0.875 + 0.25 = 1.125 seconds

Hence, the fireworks will explode after 1.125 seconds of launching Firework B.

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