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How can (1/4)x-3=(1/2)x+8 be set up as a system of equations?

4y + 4x = −12

2y + 2x = 16


4y − x = −12

2y − x = 16


4y + x = −12

2y + x = 16


4y − 4x = −12

2y − 2x = 16

Verified Answer :

MissPhiladelphia

Thank you for posting your question here at brainly. Feel free to ask more questions.   

The best and most correct answers among the choices provided by the question are: 

4y − x = −12
2y − x = 16 

Hope my answer would be a great help for you.  

Answer:

option (2) is correct.

The set up for the given equation as a system of equations is

4y − x = −12

2y − x = 16  

Step-by-step explanation:

   Given : \(\frac{1}{4}x-3=\frac{1}{2}x+8\)

We have to set up the given equation as a system of equations.

The given equation has two sides right side and left side since, LHS = RHS , so we can put both sides equal to a single variable say y ,

Thus, \(\frac{1}{4}x-3=y\)   ..........(1)

\(\frac{1}{2}x+8=y\) .....(2)

We have obtained the system of equations.

Since, we have choose out of given options , so we will simplify the above two equations, as

Multiply equation (1) by 4 , we get,

(1) ⇒ \(x-12=4y\)

Taking variable one side we get,  4y - x = -12

Multiply equation (2) by 2 , we get,

(2) ⇒ \(x+16=2y\)

Taking variable one side we get,  2y - x = 16

Thus, option (2) is correct.

The set up for the given equation as a system of equations is

4y − x = −12

2y − x = 16  

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