Answer:
\(D=2\sqrt{\frac{A}{3.14}}\)
Step-by-step explanation:
we know that
The area of a circle is
\(A=3.14r^{2}\) ----> equation A
The diameter of a circle is
\(D=2r\) ----> equation B
Solve for r in the equation A
That means ---> isolate the variable r
Divide by 3.14 both sides
\(\frac{A}{3.14}=r^{2}\)
take the square root both sides
\(\sqrt{\frac{A}{3.14}}=r\)
Rewrite
\(r=\sqrt{\frac{A}{3.14}}\)
Substitute the value of r in the equation B
\(D=2\sqrt{\frac{A}{3.14}}\)
