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Vitellium (Vi) has the following composition:

Vi–188: 187.9122 amu; 10.861%

Vi–191: 190.9047 amu; 12.428%

Vi–193: 192.8938 amu; 76.711%

Based on this data, what can you predict about the average atomic mass of vitellium?

Verified Answer :

MoSikder

192.1055 to 4 decimal places. If you want the workings out, don't hesitate to ask.

dsdrajlin

Answer:

The average atomic mass of vitellium is 192.11 amu.

Explanation:

The average atomic mass is an average between the masses of all the isotopes, considering their abundance in the nature. It can be calculated using the following expression:

\(AAM=\frac{\Sigma m_{i} \times ab_{i}  }{100}\)

where,

\(m_{i}\) is the mass of each isotope.

\(ab_{i}\) is the abundance in the nature of each isotope.

For vitelium,

\(AAM=\frac{187.9122amu \times 10.861 + 190.9047amu \times 12.428 + 192.8938 amu\times 76.711 }{100} =192.11amu\)

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