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When factoring a trinomial of the form ax2 + bx + c where a and b are both positive and c is negative, you need to find two numbers, m and n, such that ax2 + bx + c = ax2 + mx + nx + c and _________.

A.

m and n are both positive

B.

m and n are both negative

C.

m is positive, n is negative, and |m|>|n|

D.

m is positive, n is negative, and |n|>|m|

Verified Answer :

m n = a c
Since a and b are positive and c is negative.
So, a c is negative which means that m n is negative, i.e. m is positive, n is negative.

Also m + n = b and since b is positive, then |m| > |n|.

Therefore, option C is the correct answer.

Answer:

Step-by-step explanation:

Wrong. I just took the test and it's D.

Here's why:

when ax2-[mx+nx]-c

m and n need to have a positive and a negative coefficient.

if m is positive and a n is negative then n needs to be greater than m so the solution will also be negative to satisfy the need for [mx+nx] to be negative.

;)