Answer: c) 10.0
Explanation:
The balanced equilibrium reaction will be,
\(N_2O_4(g)\rightleftharpoons 2NO_2(g)\)
Concentration of \(NO_2\) at equilibrium = 0.500 M
Concentration of \(N_2O_4\) at equilibrium = 0.0250 M
The expression for equilibrium reaction will be,
\(K_{eq}=\frac{[NO_2]^2}{[N_2O_4]}\)
Now put all the given values in this expression:
\(K_{eq}=\frac{(0.500)^2}{(0.0250)}\)
\(K_{eq}=10.0\)
Therefore, the equilibrium constant is 10.0.
