Answer:
Step-by-step explanation:
It is given that the value of sinx is \(\frac{1}{2}\).
Since, we know that \(sinx=\frac{Perpendicular}{hypotenuse}=\frac{1}{2}\), thus value of perpendicular is 1 and hypotenuse is 2.
Now, the value of the base will be:
\((Hyp)^{2}=(base)^{2}+(Perpendicular)^{2}\)
\((2)^2=(B)^2+(1)^2\)
\(4-1=(B)^2\)
\(Base=\sqrt{3}\)
Now, the value of \(tanx=\frac{P}{B}=\frac{1}{\sqrt{3}}\) and the value of \(cosx=\frac{B}{H}=\frac{\sqrt{3}}{2}\).
