Answer:
84% of the scores are less than 81.
Step-by-step explanation:
Here,
The given distribution is in normal distribution.
Mean = 74
Standard deviation = 7
Approximately 68% of the data falls within one standard deviation of the mean (or between the mean -one times the standard deviation, and the mean + 1 times the standard deviation).
As 81 = 74+7 = μ+1σ
So, \(\dfrac{64}{2}=34\%\) of scores will be between 74 and 81.
As 74 is the mean, so 50% of score will lie below 74.
So total of 50+34=84% of the score will be less than 81.
