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∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices A'(-1, 1), B'(-2, -1), C(-1, 0). What are the vertices of ∆ABC?

Verified Answer :

A (-1,1) B (1,2) C (0,1)

Answer: \(A(-1,1),B(1,2),C(0,1)\)

Step-by-step explanation:

The rule to reflected a figure about the line y=-x on graph is given by :-

\((x,y)\rightarrow(-y,-x)\)

Therefore, if ∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices \(A'(-1, 1), B'(-2, -1), C(-1, 0)\).

Then, the vertices of ∆ABC will be :_

\(A'(-1, 1)\rightarrow\ A(-1,1)\\B'(-2, -1)\rightarrow\ B(1,2)\\C(-1, 0)\rightarrow\ C(0,1)\)

The vertices of ∆ABC= \(A(-1,1),B(1,2),C(0,1)\)