∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices A'(-1, 1), B'(-2, -1), C(-1, 0). What are the vertices of ∆ABC?
Answer: \(A(-1,1),B(1,2),C(0,1)\)
Step-by-step explanation:
The rule to reflected a figure about the line y=-x on graph is given by :-
\((x,y)\rightarrow(-y,-x)\)
Therefore, if ∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices \(A'(-1, 1), B'(-2, -1), C(-1, 0)\).
Then, the vertices of ∆ABC will be :_
\(A'(-1, 1)\rightarrow\ A(-1,1)\\B'(-2, -1)\rightarrow\ B(1,2)\\C(-1, 0)\rightarrow\ C(0,1)\)
The vertices of ∆ABC= \(A(-1,1),B(1,2),C(0,1)\)