For an angle Θ with the point (12, −5) on its terminating side, what is the value of cosine?
Well, in order to answer this problem we need to use the the Pythagorean Theorem and the it will be like this:
cos = x / hypotenuse
cos= 12/13
I think with this you can figure the rest out. Hope this helps
Answer:
The value of cosine is \(\frac{12}{13}\).
Step-by-step explanation:
It is given that an angle \({\theta}\), with the point (12,-5) is on its terminating side, then the adjacent sides has measure =12 and the opposite side has measure =-5.
Now, from the figure drawn, using the Pythagoras theorem, we have
\((Hyp)^2=(Base)^2+(Per)^2\)
⇒\((H)^2=(12)^2+(-5)^2\)
⇒\((H)^2=144+25\)
⇒\((H)^2=169\)
⇒\(H=13\)
Thus, the value of hypotenuse is 13units.
Now, the value of cosine is given as:
\(cosine=\frac{adjacent}{hypotenuse}\)
⇒\(cosine=\frac{12}{13}\)
Therefore, the value of cosine is \(\frac{12}{13}\).