Verified Answer :

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\(3x-5y=11 \\ x=3y+1 \\ \\ \hbox{substitute 3y+1 for x in the 1st equation and solve for y:} \\ 3(3y+1)-5y=11 \\ 9y+3-5y=11 \\ 4y+3=11 \\ 4y=11-3 \\ 4y=8 \\ y=\frac{8}{4} \\ y=2 \\ \\ \hbox{now substitute 2 for y in one of the equations and solve for x:} \\ x=3 \times 2 +1 \\ x=6+1 \\ x=7 \\ \\ \hbox{the answer:} \\ x=7 \\ y=2\)

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