the line of symmetry of y = 2x^2 - 4x + 1.
the axis of symmetry of x= - b/2a, so the line of symmetry is x= - 4/2x2= -1
x=-1
the values of a, b, and c from the general form of the equation (2x + 1)(x - 2) =(2x + 1)(x - 2) = 2x²-4x+x-2=2x²-3x-2=ax²+bx+c=0
by identifying, a =2, b=-3 and c=-2
the line of symmetry for the graph of y = -3x^2 + 12x - 11 is x= -b/2a, so
x= -12/2x-3=2, x=2
The x-coordinate of the vertex of the parabola whose equation is y = 3x2 + 9x, x=-b/2a=-9/6=-3/2
The line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = -2. What is the value of "a"
y = ax2 - 4x + 3, x=-b/2a=-2, implies -b=-2x2a, -(-4)=-2x2a, 4= -4a, a=-1
