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yeidalizferrer
yeidalizferrer yeidalizferrer
  • 11-01-2015
  • Mathematics
Answered

how to solve

3/5e-6=-2/5(e-10)-7

Verified Answer :

macio06 macio06
  • 11-01-2015

\(\frac{3}{5} e-6=- \frac{2}{5}(e-10)-7\)
\(\frac{3}{5} e-6=- \frac{2}{5} e- \frac{2}{5}*(-10) -7 \\ \frac{3}{5} e-6=- \frac{2}{5} e+ \frac{20}{5} -7= \frac{3}{5} e-6=- \frac{2}{5} e+4 -7= \\\)
\(\frac{3}{5}e-6=- \frac{2}{5} e-3\)      /*5
3e-18=-2e-15        /+15
3e-3=-2e            /+2e
5e-3=0              /+3
5e=3
e=\(\frac{3}{5}\)

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