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Given the venn diagram below, if a student is randomly selected, what is the probability that he or she is not attending both colleges?

A82%
B84%
C86%
D80%

Given the venn diagram below, if a student is randomly selected, what is the probability that he or she is not attending both colleges? A) 82 B) 84 C) 86 D) 80 class=

Verified Answer :

Answer: I’m pretty sure 86%,C

Step-by-step explanation:

Add up all the numbers provided (64+28+52+56)=200.

Then divide 28 by 200 this is 14. After, subtract 100%-14%, therefore you get 86%

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Number of people attended Texas only = 64

Number of people attended Binn = 52

Number of people attended both = 28

Number of people not attending any colleges = 56

Total number of people = 64+52+28+56 = 200

Probability of people attending both is given by

\(\dfrac{28}{200}\times 100\\\\=14\%\)

So, Probability of people not attending both colleges is given by

\(100\%-14\%\\\\=86\%\)

Hence, Option 'C' is correct.