\(\frac{x}{2}\) is equivalent to the product of \(\sqrt{\frac{3x}{2} } .\sqrt{\frac{x}{6} }\) .
What is the law for square root?
As for square roots, a number r is a square root of a number x if r^2 = x.
According to the question.
We have a expression in the form of square root.
\(\sqrt{\frac{3x}{2} } .\sqrt{\frac{x}{6} }\)
Therefore, the product of \(\sqrt{\frac{3x}{2} }\) and \(\sqrt{\frac{x}{6} }\) is given by
\(\sqrt{\frac{3x}{2} } \sqrt{\frac{x}{6} }\)
=\(\sqrt{\frac{(3x)(x)}{(6)(2)} }\)
=\(\sqrt{\frac{x^{2} }{4} }\)
=\(\frac{x}{2}\)
Hence,\(\frac{x}{2}\) is equivalent to the product of \(\sqrt{\frac{3x}{2} } .\sqrt{\frac{x}{6} }\)
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