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Verified Answer :

johnkellock

Square of quantity x plus three means : x+3/√

quantity x plus eight means : (x+8)

quantity x minus two means : (x−2)


Therefore :
f(x)=x+3 / √(x+8)×(x−2)

R:x≥−3

Answer:

[-3,2)U(2,∞)  domain of the function

Step-by-step explanation:

We have given function : \(f(x) =\frac{\sqrt{x+3}}{(x+8)(x-2)}\)

To find : The domain of the given function

Solution : Domain is where the function is defined

So, we distribute the function,

1) \(f(x) =\sqrt{x+3}\)

\(x\geq-3\)

2) \(f(x) =(x+8)(x-2)\)

\(x<2\)

Therefore, the domain of the function

[-3,2)U(2,∞)

or x∈real no. : -3≤x<2


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