Hagrid
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What is the equation of the plane that contains the triangle shown in the diagram?



2x + 3y + z = 6


2x + 3y + 6z = 12


3x + 2y + 6z = 0


6x + 2y + 3z = 18

What is the equation of the plane that contains the triangle shown in the diagram? 2x + 3y + z = 6 2x + 3y + 6z = 12 3x + 2y + 6z = 0 6x + 2y + 3z = 18 class=

Verified Answer :

the first equation

2x + 3y + 6z = 12

Answer:

Option A is correct.

\(2x + 3y +z = 6\)

Step-by-step explanation:

The intercept form of the equation of plane is given by:

\(\frac{x}{l}+\frac{y}{m} +\frac{z}{n} =1\)            .....[1]

where

l is the intercept of x-axes

m is the intercept of y-axes and

n is the intercept of z-axes respectively;

From the given figure;

we have;

The intercepts of coordinates axes are;

\(l = 3\)

\(m = 2\)

\(n = 6\)

Substitute these values in the equation [1]; we have;

\(\frac{x}{3}+\frac{y}{2} +\frac{z}{6} =1\)  

Taking LCM of 3, 2 and 6 is 6

\(2x + 3y +z = 6\)

therefore, the equation of plane that contains the triangle as shown in the diagram is, \(2x + 3y +z = 6\)