A small smooth ring R of weight 8.5N is threaded on a light inextensible string. The ends of the

string are attached to fixed points A and B, with A vertically above B. A horizontal force of magnitude

15.5N acts on R so that the ring is in equilibrium with angle ARB = 90◦. The part AR of the string

makes an angle q with the horizontal and the part BR makes an angle q with the vertical (see diagram).

The tension in the string is T N. Show that T sin q = 12 and T cos q = 3.5 and hence find q.