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An inequality is shown below: −np − 6 ≤ 3(c − 5)

Which of the following solves for n?

n ≥ − the quantity 3 times c minus 21 all over p


n ≥ − the quantity 3 times c minus 9 all over p


n ≤ − the quantity 3 times c minus 21 all over p


n ≤ − the quantity 3 times c minus 9 all over p

Verified Answer :

B..............
c>=3 and n<0 and p<=(9-3 c)/n

Answer:

n ≥ − the quantity 3 times c minus 9 all over p

Step-by-step explanation:

To solve inequalities you should use the same method as to solve equalities.

1. First write down the inequality:

\(-np-6\leq 3(c-5)\)

2. Solve the parentheses:

\(-np-6\leq 3c-15\)

3. Pass the independent numbers to the right side of the inequality with opposite sign and do the mathematical operations:

\(-np\leq 3c-15+6\\\\-np\leq 3c-9\)

4. Pass the p with the minus sign to the right side of the inequality, as p has the minus sign, the direction of the inequality changes:

\(n\geq -(\frac{3c-9}{p})\)