we have
\(4x-y=1\)
This is the equation of the line in standard form
so
The graph is a straight line
we are going to proceed to verify the first two cases only
case A) It is a straight line joining the points \((0, -1)\), \((1, 3)\), and \((-1, -5)\)
Using a graphing tool
The three points are on the straight line
see the attached figure N \(1\)
case B) It is a straight line joining the points \((4,-3)\), \((-1, 2)\), and \((-4, 5)\)
Using a graphing tool
The three points are not in the straight line
see the attached figure N \(2\)
therefore
the answer is
It is a straight line joining the points \((0, -1)\), \((1, 3)\), and \((-1, -5)\)
