Answer:
There are 8.24 moles in \(4.96\times 10^{24}\) molecules of glucose.
Explanation:
\(N=n\times N_A\)
Where:
N = Number of particles / atoms/ molecules
n = Number of moles
\(N_A=6.022\times 10^{23} mol^{-1}\) = Avogadro's number
We have:
N = \(4.96\times 10^{24}\) molecules of glucose
n =?
\(n=\frac{N}{N_A}=\frac{4.96\times 10^{24}}{6.022\times 10^{23} mol^{-1}}\)
n = 8.24 moles
There are 8.24 moles in \(4.96\times 10^{24}\) molecules of glucose.
