in the reaction 3H2+N2--> NH3,what coefficient should be placed in front of NH3 to balance the reaction?
The best way to solve this is to list all the elements out and count them.
Count subscripts first (if there is no subscript then there is 1 atom)
Then multiply by the coefficients
To balance write a coefficient and multiply
3H2+N2--> NH3
H 2 x 3 = 6 H 3 (x2) = 6
N 2 N 1 (x2) = 2
Your answer is 2 . . . to balance this equation you will need a coefficient of 2
Answer:
2
Explanation:
To balance the equation there must be the same numbers of atoms at the left side and at the right side. So, at the left side we have:
6 atoms of H (3 x 2)
2 atoms of N (1 x 2)
And at the right side we have:
1 atom of N (1 x 1)
3 atoms of HN (1 x 3)
If you multiply these last by 2, you will have:
2 atoms of N (2 x 1)
6 atoms of H (2 x 3)
Then, the numbers of atoms of H and N at the left side is equal to the numbers of atoms of H and N at the right side. The balanced equation is:
3H2+N2--> 2NH3