Answer:
False, \(i^2
eq \sqrt{2}\)
Step-by-step explanation:
\(i\) is defined as:
\(i=\sqrt{-1}\)
so \(i^2\) must be:
\(i^2=(\sqrt{-1})^{2}\)
The square root and the squared power are inverse operations, so they cancel ech other
\(i^2=-1\)
so it is concluded that \(i^2\) is not equal to \(\sqrt{2}\), but instead is equal to \(-1\)
