In which quadrant does the solution of the system fall?
y=x-1
y=-3x-5
a. 1
b. 2
c. 3
d. 4
In which quadrant does the solution of the system fall?
x+y=4
2x-y=2
a. 1
b. 2
c. 3
d. 4
The cost of four scarves and six hats is $52.00. The cost of two hats is $1.00 more than the cost of one scarf. What is the cost of one scarf?
a. $4.00
b. $
5.00
c. $6.00
d. $
7.00

Verified Answer :

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Answer:

First Question: C

Second Question: A

Third Question: D


Step-by-step explanation:


First Question:


We need to solve the equation first and see the x and y point of the solution.

We can substitute Equation 1 into Equation 2 given, and then solve for x:

\(x-1=-3x-5\\x+3x=-5+1\\4x=-4\\x=\frac{-4}{4}=-1\)

Now putting  \(x=-1\)  into the first equation, we get y:

\(y=(-1)-1\\y=-2\)

Hence, the solution is x = -1 and y = -2

Both x and y negative falls in the 3rd quadrant.

Answer choice C is right.


Second Question:


Let's solve the equation using substitution method and find the solution first.

Solving for x in Equation 1 gives us:

\(x=4-y\)

Now using this and substituting in Equation 2 we have:

\(2(4-y)-y=2\)

Now using distributive property [ \(a(b+c)=ab+ac\) ] and a little algebra, we solve for y:

\(2(4-y)-y=2\\8-2y-y=2\\8-3y=2\\8-2=3y\\6=3y\\y=\frac{6}{3}=2\)

Now using value of  \(y=2\)  and putting it in the First Equation and rearranging gives us the value of x:

\(x+(2)=4\\x=4-2\\x=2\)

So our solution is  \(x=2\)  and  \(y=2\)

Both x and y are positive and they fall in 1st quadrant.

Choice A is right.


Third Question:

We let cost of  one scarf be  \(s\)  and cost of one hat be  \(h\)


"The cost of four scarves and six hats is $52.00":

Cost of 4 scarves is  @@MATH_TOKEN_13@@  and the cost of 6 hats is  @@MATH_TOKEN_14@@

The total cost is $52, hence we can write our first equation:

\(4s+6h=52\)


"The cost of two hats is $1.00 more than the cost of one scarf":

Cost of 2 hats is  @@MATH_TOKEN_16@@  and cost of one scarf is  @@MATH_TOKEN_17@@  , so from information given we can write second equation as:

@@MATH_TOKEN_18@@


We have 2 equations. Now solving for  @@MATH_TOKEN_19@@  in second equation and putting that into first equation, we have:

@@MATH_TOKEN_20@@

Now,

@@MATH_TOKEN_21@@

Using distributive proper [ @@MATH_TOKEN_22@@ ] and a little algebra, we can find the value of s:

@@MATH_TOKEN_23@@

Hence, the cost of 1 scarf is $7.00

Answer choice D is right.