The endpoints of EF are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of EF?
I guess you are looking for a general way of writing a midpoint in coordinate system.
we have the following:
E(xe, ye) and F(xf,yf)
then mind point is as follows
((xe+xf)/2, (ye+yf)/2)
Answer:
The coordinates of the midpoint of EF is equal to
\((\frac{xE+xF}{2},\frac{yE+yF}{2})\)
Step-by-step explanation:
we know that
The formula to calculate the midpoint between two points is equal to
\(M=(\frac{x1+x2}{2},\frac{y1+y2}{2})\)
In this problem we have
\((x1,y1)=(xE,yE)\)
\((x2,y2)=(xF,yF)\)
Substitute the values in the formula
\(M=(\frac{xE+xF}{2},\frac{yE+yF}{2})\)