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Verified Answer :

we know that

\(G=60\°\)

The value of the tangent is equal to

\(tan(G)=\frac{sin(G)}{cos(G)}\)

remember that

\(sin(60\°)=\frac{\sqrt{3}}{2}\)

\(cos(60\°)=\frac{1}{2}\)

substitute

\(tan(60\°)=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}\)

\(tan(60\°)=\sqrt{3}\)

therefore

the answer is

square root 3

Answer:

(D)

Step-by-step explanation:

It is given that GYK is a right angled triangle, which is right angled at K and the measure of the angle G is 60° and the measure of the angle Y is 30°.

Now, from the ΔGYK, using the trigonometry, we have

\(tanG=\frac{sinG}{cosG}\)

Now,the value of \(sinG\) is :

\(sinG=sin(60^{\circ})\)

=\(\frac{\sqrt{3}}{2}\)

And, the value of \(cosG\) is:

\(cosG=cos(60^{\circ})\)

=\(\frac{1}{2}\)

Now, the value of \(tanG\) is:

\(tanG=\frac{sinG}{cosG}\)

\(tan(60^{\circ})=\frac{sin60^{\circ}}{cos60^{\circ}}\)

\(tan60^{\circ}=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}\)

\(tan60^{\circ}=\sqrt{3}\)

Thus, option D is correct.