what is the average kinetic energy of 1 mole of gas at 102 degree celsius
R= 8.314 J/mol K
T= 273 + 102 = 375K
= (3/2) x 8.314 x 375 = 4680 J/mol
Answer:
The average kinetic energy of the gas is 4.678 kJ/mol.
Explanation:
Average kinetic energy of the gas id defined as measure of an average kinetic energy possessed by each particle of the gas.
It is given as:
\(K=\frac{3}{2}RT\) (Average kinetic energy per mole)
\(K=\frac{3}{2}kT\) (Average kinetic energy per molecule)
R = Universals gas constant\(8.314 J /mol K\)
T = temperature of the gas
k = Boltzmann constant = \(1.38\times 10^{-23} J/K\)
The average kinetic energy of 1 mole of gas at 102°C:
T = 102°C = 375.15 K[/tex]
\(K=\frac{3}{2}\times 8.314 J/mol K\times 375.15 K=4,678.49 J/mol=4.678 kJ/mol\)
The average kinetic energy of the gas is 4.678 kJ/mol.