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Verified Answer :

R= 8.314 J/mol K
T= 273 + 102 = 375K


= (3/2) x 8.314 x 375 = 4680 J/mol

Answer:

The average kinetic energy of the gas is 4.678 kJ/mol.

Explanation:

Average kinetic energy of the gas id defined as measure of an average kinetic energy possessed by each particle of the gas.

It is given as:

\(K=\frac{3}{2}RT\) (Average kinetic energy per mole)

\(K=\frac{3}{2}kT\) (Average kinetic energy per molecule)

R = Universals gas constant\(8.314 J /mol K\)

T = temperature of the gas

k = Boltzmann constant = \(1.38\times 10^{-23} J/K\)

The average kinetic energy of 1 mole of gas at 102°C:

T = 102°C = 375.15 K[/tex]

\(K=\frac{3}{2}\times 8.314 J/mol K\times 375.15 K=4,678.49 J/mol=4.678 kJ/mol\)

The average kinetic energy of the gas is 4.678 kJ/mol.