\(2v2 -5v +3 = 0 \\ \\\Delta = b^{2}-4ac = (-5)^{2}-4*2*3= 25-24=1\\ \\v_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{5- \sqrt{1 }}{2*2}=\frac{5- 1}{4}= \frac{4}{4}=1\\ \\v_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{5+ \sqrt{1 }}{2*2}=\frac{5+1}{4}= \frac{6}{4}=\frac{3}{2}=1\frac{1}{2}\)
