Answer:
B. -2/3
Step-by-step explanation:
We are given a equation of line:
2y-3x=8
y=\(\dfrac{3}{2}\times x+ 4\)
Hence, slope of this line=3/2
(since, slope of line y=mx+c is m)
Now if two lines are perpendicular with sl,opes m1 and m2 then,
m1×m2=-1
\(\dfrac{3}{2}\times m2=-1\\\\\\m2=\dfrac{-2}{3}\)
Hence, slope of line perpendicular to the l;ine 2y-3x=8 is:
B. -2/3
