Answer:
\(2x-y+1=0\)
Step-by-step explanation:
The given points are,
\((-2,-3),(-1,-1),(0,1),(1,3),(2,5)\)
The difference in x coordinates is 1 and the difference in y coordinates is also 1. As change in both x and y are same and constant, so graph will be a straight line.
Plotting the points on the Cartesian coordinates, we get a straight line.
Applying two point formula, taking (-2,-3), (-1,-1), we get
\(\Rightarrow \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}\)
\(\Rightarrow \dfrac{y+3}{-1+3}=\dfrac{x+2}{-1+2}\)
\(\Rightarrow \dfrac{y+3}{2}=\dfrac{x+2}{1}\)
\(\Rightarrow y+3=2(x+2)\)
\(\Rightarrow y+3=2x+4\)
\(\Rightarrow 2x-y+1=0\)
