Aaron is calculating the difference (D) between the areas of two circles. If Circle 1 has a radius of R, Circle 2 has a radius of r, R>r, which of the following equations represents the difference between the areas?

AD= π(R-r)^2
BD= π(R^2-r^2)
CD= π^2(R-r)
DD= (πR-πr)^2

Question

19-12-2016
Mathematics

Answered

Aaron is calculating the difference (D) between the areas of two circles. If Circle 1 has a radius of R, Circle 2 has a radius of r, R>r, which of the following equations represents the difference between the areas?

AD= π(R-r)^2
BD= π(R^2-r^2)
CD= π^2(R-r)
DD= (πR-πr)^2

Verified Answer :

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Anonymous Anonymous · Answer 1 · 2016-12-23T13:17:20-05:00

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
y = (2/3)x - 3
3y = 2x - 9 ( multiplied both sides by 3)
-2x + 3y = -9 (subtracted 2x from both sides)
-2x + 3y + 9 = 0 (added 9 to both sides)
-2x + 3y + 9 = 0 is standard form of a straight line

if you prefer the coefficient of x to be positive, you can multiply the above by -1:
2x - 3y - 9 = 0

Aaron is calculating the difference (D) between the areas of two circles. If Circle 1 has a radius of R, Circle 2 has a radius of r, R>r, which of the following equations represents the difference between the areas? AD= π(R-r)^2BD= π(R^2-r^2)CD= π^2(R-r)DD= (πR-πr)^2

Verified Answer :

Related Questions

Aaron is calculating the difference (D) between the areas of two circles. If Circle 1 has a radius of R, Circle 2 has a radius of r, R>r, which of the following equations represents the difference between the areas?

AD= π(R-r)^2
BD= π(R^2-r^2)
CD= π^2(R-r)
DD= (πR-πr)^2