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At high temperatures, steam decomposes into its elements according to the following equation.

2H2O(g) 2H2(g) + O2(g)

In one experiment at 1 atm pressure, it was found that 20% of the steam had been converted into

hydrogen and oxygen.

What are the values of the equilibrium partial pressures, in atm, of the components of this

equilibrium?

Verified Answer :

ZavierL

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20% steam converted, 0.8atm of steam remains
Converted to 0.2atm H2(g) and 0.1atm O2(g)
Partial Pressure of
H2O(g) =0.8/1.1 =0.727atm
H2(g) = 0.2/1.1 =0.181atm
O2(g) = 0.1/1.1 = 0.091atm

Answer:

Explanation:

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