An olympic sprinter can go from a state of rest to 11 meters per second in 10 seconds. What is the sprinter's average acceleration?
Since I think the formula for acceleration is a=d/t you plug in 11 for d and 10 for t and get 11/10=1.1 so 1.1 m/s is his/her acceleration.
Answer: Sprinter's average acceleration = \(1.1\frac{m}{s^2}\)
Explanation:
The formula for the average acceleration is given as follows:
\(\overline{a} = \frac{v_f - v_i}{\Delta t}\) --- (A)
Where,
\(v_f\) = Final velocity = \(11\frac{m}{s}\)
\(v_i\) = Initial velocity = \(0\frac{m}{s}\)
\(\Delta t\) = Elapsed time = 10 seconds
Plug the values in equation (A):
\(\overline{a} = \frac{11 - 0}{10} = 1.1\frac{m}{s^2}\)
Therefore, the sprinter's average acceleration is \(1.1\frac{m}{s^2}\).